Laravel Query Builder Join with subquery Example – Technology

Today, We want to share with you Laravel Query Builder Join with subquery Example.In this post we will show you Laravel 5 Join with subquery in Query Builder Example, hear for How to select from subquery using Laravel Query Builder? we will give you demo and example for implement.In this post, we will learn about laravel eloquent left join subquery with an example.

Laravel Query Builder Join with subquery Example

There are the Following The simple About Laravel Query Builder Join with subquery Example Full Information With Example and source code.

As I will cover this Post with live Working example to develop Add a left join in Laravel query/subquery builder, so the some major files and Directory structures for this example is following below.

$users_master_data = DB::table("users")
  ->select("users.*","users_count.user_group","users_count.usersub_group")
  ->join(DB::raw("(SELECT 
      users_count.id_user,
      GROUP_CONCAT(users_count.ugrp) as user_group,
      GROUP_CONCAT(users_count.subgp) as usersub_group
      FROM users_count
      GROUP BY users_count.id_user
      ) as users_count"),function($join){
        $join->on("users_count.id_user","=","users.id");
  })
  ->groupBy("members.id")
  ->get();
dd($users_master_data);

Laravel join with subquery

$data_members = DB::table("members")
      ->select("members.*",
              DB::raw("(SELECT count(*) FROM item_followers
                      WHERE item_followers.user_id = members.id
                    ) as total_followers"))
      ->get();
dd($data_members);    

Laravel Sub-Query Joins

$latestsuggestions = DB::table('members')
->select('sugestor_id', DB::raw('MAX(created_at) as last_suggestions_created_at'))
->where('is_published', true)
->groupBy('sugestor_id');

$sugestors = DB::table('sugestors')
->joinSub($latestsuggestions, 'latest_suggestions', function($join) {
$join->on('sugestors.id', '=', 'latest_suggestions.sugestor_id');
})->get();

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